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(25^x-1)/(5^x+1)=24
We move all terms to the left:
(25^x-1)/(5^x+1)-(24)=0
Domain of the equation: (5^x+1)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
5^x!=-1
x!=-1/1
x!=-1
x∈R
(25^x-1)-24*(5^x+1)=0
We multiply parentheses
(25^x-1)-120x-24=0
We get rid of parentheses
25^x-120x-1-24=0
We add all the numbers together, and all the variables
-120x+25^x-25=0
We move all terms containing x to the left, all other terms to the right
-120x+25^x=25
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